Oxidation Numbers
 Oxidation
Number Rules
1.
The oxidation number of un-combined elements is zero.
2.
In simple ions the oxidation number of the element is
the charge on the ion
3.
The sum of the oxidation numbers in a neutral
compound is zero.
4.
The sum of the oxidation numbers for an ion is the
charge on the ion.
5.
Some elements have fixed oxidation numbers in all
their compounds
Metals Non-metals
Group I metals +1 hydrogen
+1 (except in metal hydrides, H-)
Group II metals +2 fluorine -1
Aluminium +3 oxygen -2 (except in
peroxides O22-
and compounds with fluorine).
chlorine -1 (except in compounds
with oxygen / fluorine).
Problems
1.
Calculate the oxidation state of sulphur in the
sulphate ion (SO42-)
Step 1: Allocate known charges
x = charge on sulphur
overall charge = -2
charge on each oxygen = -2
Step 2: Write equation
x + (4×-2) = -2
x – 8 = -2
x = -2+8
x = +6
Oxidation state of sulphur
in SO4-2 = +6
Always remember to include
the fact that these are positive or negative – DON’T Assume!
2.
Calculate the charge on the manganese in the MnO4-
ion.
3.
Calculate the charge on the chromium in Cr2O72-.
Calculate the oxidation states of the starred ions in
these compounds.
1. Br*O-
2. Br*O3- 3. HBr 4. N*H4+
5. P*Cl5
6. S*O32- 7. N*O2-
8. S*2O32-
Some formulae have roman numerals e.g. iron (II)
bromide. This number gives the oxidation states of the iron.
The compound CuSO4½H2O
is commonly called copper (II) sulphate. Its correct name is tetraaquocopper
(II) tetraoxosulphate (VI)-1-water. However very few chemists call is this
and copper (II) sulphate is acceptable.
Write the formulae of these compounds.
a)
tin (II) oxide
b)
tin (IV) oxide
c)
sodium chlorate (III)
d)
iron (III) nitrate (V)
e)
potassium chromate (VI)
Use the concept of oxidation states to help you balance
these equations, state what is oxidised and which is reduced.
a)
Fe + Br2
? FeBr3
b)
F2 + H2O
? HF + O2
c)
IO3- + H+ + I-
? I2 + H2O
d)
S2O32- + I2
? S4O62-
+ I-
e) Cl2 + OH-
?
Cl- + ClO- + H2O |